Lets count to a million!

[xounstaer]

6091

how stupid can be fun ah

can we do it hexadecimal or bipolair or how do you call that again wait i'll see

10110000111110000000110100101001000100110011001100101111110010100101111001101100110111011011011101101011100110100000000111000000001


ac109xfh


haha

sixthousandninetyone.


would be fun btw

0
1
10
11
100
101
110
111
1000

that 8

 

[Theofilus]

6091

how stupid can be fun ah

can we do it hexadecimal or bipolair or how do you call that again wait i'll see

10110000111110000000110100101001000100110011001100101111110010100101111001101100110111011011011101101011100110100000000111000000001


ac109xfh


haha

sixthousandninetyone.


would be fun btw

0
1
10
11
100
101
110
111
1000

that 8

I've done it in binary (not bipolar, thta's a mental disease), hexadecimal (aka hex) and octal (base 8). I think the binary number you posted is a bit big, though. 6092, written as a 16 bit binary number is

0001 0111 1100 1100 (spaces added to make it easier to read) The same number in hex is 17CC and in octal, it's 13714

 

[xounstaer]

6093

 

[l'Chante]

6094

 

[Theofilus]

(in hexadecimal notation)
17CF, 17D0, 17D1, 17D2, 17D3, 17D4, 17D5, 17D6, 17D7,
17D8, 17D9, 17DA, 17DB, 17DC, 17DD, 17DE, 17DF, 17E0

 

[l'Chante]

............uh, next?

 

[Theofilus]

6094

(in hexadecimal notation)
17CF, 17D0, 17D1, 17D2, 17D3, 17D4, 17D5, 17D6, 17D7,
17D8, 17D9, 17DA, 17DB, 17DC, 17DD, 17DE, 17DF, 17E0

............uh, next?

17E1, of course :D

That's 13741 in octal, 1011111100001 in binary and 6113 in decimal.

 

[l'Chante]

6114 / 17E2 / VI-CXIV ? This is just too much for a Monday...

 

[Theofilus]

Ah, yes... I forgot Roman numerals.

LXI - XV

 

[xounstaer]

X x(*) C = 1000
1000 = T
5000 =R
500 = V
50 = W
RTC + 15 = Q

Q is equal to 6115 (in number)

I = 1

LOL

QI



next
there's no mistake is there?

 

[Theofilus]

X x(*) C = 1000
1000 = T
5000 =R
500 = V
50 = W
RTC + 15 = Q

Q is equal to 6115 (in number)

I = 1

LOL

QI



next
there's no mistake is there?

Are those supposed to be Roman numerals? The correct way of writing Roman numerals, according to Wikipedia, is:

I = 1
V = 5
X = 10
L = 50
C = 100
D = 500
M = 1000

You can't have more than one of any letter representing a number that starts with 5 in our numbering system. In other words, you can only have one V, L or D in a single number. The other letters - I, X, C and M - can occur, at most, 3 times in a row. The highest number you can write, according to these rules is MMMCMXCIX, or 3,999. To write numbers higher than that, you would have to draw a horizontal line above a letter, to multiply it by 1000. V, with a line over it, represents 5,000. An overlined I represents 1000. Since I can't make overlines in this editor, I'll use underlines instead. The next number (6117) in Roman numerals is...

VIXVII

 

[xounstaer]

ow wait yes i can underline

btw there was no mistake was there? it was a mixture:D

IIQ

 

[xounstaer]

QIIV

6118

 

[l'Chante]

6
1
1
9

 

[Theofilus]

153*40

 

[l'Chante]

13466.2 lb = ...kg

 

[Theofilus]

9,795.2 km = ???? mi.

 

[l'Chante]

9,795.2 km = ???? mi.

I get to 6086.4? What am I doing wrong? 4

1 Kilometer = 0.621371192237334 Miles


6123

 

[Theofilus]

I get to 6086.4? What am I doing wrong? 4

1 Kilometer = 0.621371192237334 Miles


6123

You're being too accurate. I calculated using 1 mile = 1.6 km (or 1 km = 0.625 miles), but you used 1 km= 0.621371192237334 miles (or 1 mile = 1.609344 km).

9,795.2 / 1.6 = 6,122
9,795.2 * 0.625 = 6,122

13,472.8 lb = ???? kg

 

[l'Chante]

3385 Celsius to Fahrenheit :onfire